<!--
/* Font Definitions */
@font-face
{font-family:宋体;
panose-1:2 1 6 0 3 1 1 1 1 1;
mso-font-alt:SimSun;
mso-font-charset:134;
mso-generic-font-family:auto;
mso-font-pitch:variable;
mso-font-signature:3 135135232 16 0 262145 0;}
@font-face
{font-family:"\@宋体";
panose-1:2 1 6 0 3 1 1 1 1 1;
mso-font-charset:134;
mso-generic-font-family:auto;
mso-font-pitch:variable;
mso-font-signature:3 135135232 16 0 262145 0;}
/* Style Definitions */
p.MsoNormal, li.MsoNormal, div.MsoNormal
{mso-style-parent:"";
margin:0cm;
margin-bottom:.0001pt;
text-align:justify;
text-justify:inter-ideograph;
mso-pagination:none;
font-size:10.5pt;
mso-bidi-font-size:12.0pt;
font-family:"Times New Roman";
mso-fareast-font-family:宋体;
mso-font-kerning:1.0pt;}
p
{mso-margin-top-alt:auto;
margin-right:0cm;
mso-margin-bottom-alt:auto;
margin-left:0cm;
mso-pagination:widow-orphan;
font-size:12.0pt;
font-family:宋体;
mso-bidi-font-family:宋体;}
/* Page Definitions */
@page
{mso-page-border-surround-header:no;
mso-page-border-surround-footer:no;}
@page Section1
{size:612.0pt 792.0pt;
margin:72.0pt 90.0pt 72.0pt 90.0pt;
mso-header-margin:36.0pt;
mso-footer-margin:36.0pt;
mso-paper-source:0;}
div.Section1
{page:Section1;}
-->
1相等
证明：∵△ABC,△CDE都是等边三角形
∴∠ACB＝∠ECD, ∴∠BCE＝∠ACD
在△BCE和△ACD中
BC＝AC
∠BCE＝∠ACD
CE＝CD
∴△BCE≌△ACD
∴BE=AD
2相等
证明：∵△ABC,△CDE都是等边三角形
∴∠ACB＝∠ECD=60°, ∴∠ACB＝∠ECD=∠ACE=60°
∵△BCE≌△ACD, ∴∠CBF＝∠CAG
在△BCF和△ACG中
∠CBF＝∠CAG
BC＝AC
∠BCF＝∠ACG
∴△BCFE≌△ACG
∴CF=CG
3,同时到达
刘仟仟
第一行的是“c，g”