设
Zn+H2SO4=ZnSO4+H2
65 98 161 2
y x z 0.6g
98/x=2/0.6g x=29.4g
65/y=2/0.6g y =19.5g
161/z=2/0.6g z=48.3g
(1)硫酸溶液中溶质的质量分=29.4g/150g=19.6%
(2)锌粒的纯度=19.5g/24.5g=79.6%
(3)48.3g/150g+24.5g-0.6g-(24.5g-19.5g)=